5(^2x-3)=4x+5

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Solution for 5(^2x-3)=4x+5 equation: 



5(^2x-3)=4x+5

We move all terms to the left:

5(^2x-3)-(4x+5)=0

We multiply parentheses

5x-(4x+5)-15=0

We get rid of parentheses

5x-4x-5-15=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20

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